Now handles multiple hosts and targets.
[deliverable/binutils-gdb.git] / gdb / obstack.c
CommitLineData
dd3b648e
RP
1/* obstack.c - subroutines used implicitly by object stack macros
2 Copyright (C) 1988 Free Software Foundation, Inc.
3
4This program is free software; you can redistribute it and/or modify it
5under the terms of the GNU General Public License as published by the
6Free Software Foundation; either version 1, or (at your option) any
7later version.
8
9This program is distributed in the hope that it will be useful,
10but WITHOUT ANY WARRANTY; without even the implied warranty of
11MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
12GNU General Public License for more details.
13
14You should have received a copy of the GNU General Public License
15along with this program; if not, write to the Free Software
16Foundation, 675 Mass Ave, Cambridge, MA 02139, USA. */
17
18#include "obstack.h"
19
20#ifdef __STDC__
21#define POINTER void *
22#else
23#define POINTER char *
24#endif
25
26/* Determine default alignment. */
27struct fooalign {char x; double d;};
28#define DEFAULT_ALIGNMENT ((char *)&((struct fooalign *) 0)->d - (char *)0)
29/* If malloc were really smart, it would round addresses to DEFAULT_ALIGNMENT.
30 But in fact it might be less smart and round addresses to as much as
31 DEFAULT_ROUNDING. So we prepare for it to do that. */
32union fooround {long x; double d;};
33#define DEFAULT_ROUNDING (sizeof (union fooround))
34
35/* When we copy a long block of data, this is the unit to do it with.
36 On some machines, copying successive ints does not work;
37 in such a case, redefine COPYING_UNIT to `long' (if that works)
38 or `char' as a last resort. */
39#ifndef COPYING_UNIT
40#define COPYING_UNIT int
41#endif
42
43/* The non-GNU-C macros copy the obstack into this global variable
44 to avoid multiple evaluation. */
45
46struct obstack *_obstack;
47\f
48/* Initialize an obstack H for use. Specify chunk size SIZE (0 means default).
49 Objects start on multiples of ALIGNMENT (0 means use default).
50 CHUNKFUN is the function to use to allocate chunks,
51 and FREEFUN the function to free them. */
52
53void
54_obstack_begin (h, size, alignment, chunkfun, freefun)
55 struct obstack *h;
56 int size;
57 int alignment;
58 POINTER (*chunkfun) ();
59 void (*freefun) ();
60{
61 register struct _obstack_chunk* chunk; /* points to new chunk */
62
63 if (alignment == 0)
64 alignment = DEFAULT_ALIGNMENT;
65 if (size == 0)
66 /* Default size is what GNU malloc can fit in a 4096-byte block. */
67 {
68 /* 12 is sizeof (mhead) and 4 is EXTRA from GNU malloc.
69 Use the values for range checking, because if range checking is off,
70 the extra bytes won't be missed terribly, but if range checking is on
71 and we used a larger request, a whole extra 4096 bytes would be
72 allocated.
73
74 These number are irrelevant to the new GNU malloc. I suspect it is
75 less sensitive to the size of the request. */
76 int extra = ((((12 + DEFAULT_ROUNDING - 1) & ~(DEFAULT_ROUNDING - 1))
77 + 4 + DEFAULT_ROUNDING - 1)
78 & ~(DEFAULT_ROUNDING - 1));
79 size = 4096 - extra;
80 }
81
82 h->chunkfun = chunkfun;
83 h->freefun = freefun;
84 h->chunk_size = size;
85 h->alignment_mask = alignment - 1;
86
87 chunk = h->chunk = (struct _obstack_chunk *)(*h->chunkfun) (h->chunk_size);
88 h->next_free = h->object_base = chunk->contents;
89 h->chunk_limit = chunk->limit
90 = (char *) chunk + h->chunk_size;
91 chunk->prev = 0;
92}
93
94/* Allocate a new current chunk for the obstack *H
95 on the assumption that LENGTH bytes need to be added
96 to the current object, or a new object of length LENGTH allocated.
97 Copies any partial object from the end of the old chunk
98 to the beginning of the new one.
99
100 The function must be "int" so it can be used in non-ANSI C
101 compilers in a : expression. */
102
103int
104_obstack_newchunk (h, length)
105 struct obstack *h;
106 int length;
107{
108 register struct _obstack_chunk* old_chunk = h->chunk;
109 register struct _obstack_chunk* new_chunk;
110 register long new_size;
111 register int obj_size = h->next_free - h->object_base;
112 register int i;
113 int already;
114
115 /* Compute size for new chunk. */
116 new_size = (obj_size + length) + (obj_size >> 3) + 100;
117 if (new_size < h->chunk_size)
118 new_size = h->chunk_size;
119
120 /* Allocate and initialize the new chunk. */
121 new_chunk = h->chunk = (struct _obstack_chunk *)(*h->chunkfun) (new_size);
122 new_chunk->prev = old_chunk;
123 new_chunk->limit = h->chunk_limit = (char *) new_chunk + new_size;
124
125 /* Move the existing object to the new chunk.
126 Word at a time is fast and is safe if the object
127 is sufficiently aligned. */
128 if (h->alignment_mask + 1 >= DEFAULT_ALIGNMENT)
129 {
130 for (i = obj_size / sizeof (COPYING_UNIT) - 1;
131 i >= 0; i--)
132 ((COPYING_UNIT *)new_chunk->contents)[i]
133 = ((COPYING_UNIT *)h->object_base)[i];
134 /* We used to copy the odd few remaining bytes as one extra COPYING_UNIT,
135 but that can cross a page boundary on a machine
136 which does not do strict alignment for COPYING_UNITS. */
137 already = obj_size / sizeof (COPYING_UNIT) * sizeof (COPYING_UNIT);
138 }
139 else
140 already = 0;
141 /* Copy remaining bytes one by one. */
142 for (i = already; i < obj_size; i++)
143 new_chunk->contents[i] = h->object_base[i];
144
145 h->object_base = new_chunk->contents;
146 h->next_free = h->object_base + obj_size;
147}
148
149/* Return nonzero if object OBJ has been allocated from obstack H.
150 This is here for debugging.
151 If you use it in a program, you are probably losing. */
152
153int
154_obstack_allocated_p (h, obj)
155 struct obstack *h;
156 POINTER obj;
157{
158 register struct _obstack_chunk* lp; /* below addr of any objects in this chunk */
159 register struct _obstack_chunk* plp; /* point to previous chunk if any */
160
161 lp = (h)->chunk;
162 while (lp != 0 && ((POINTER)lp > obj || (POINTER)(lp)->limit < obj))
163 {
164 plp = lp -> prev;
165 lp = plp;
166 }
167 return lp != 0;
168}
169
170/* Free objects in obstack H, including OBJ and everything allocate
171 more recently than OBJ. If OBJ is zero, free everything in H. */
172
173#ifdef __STDC__
174#undef obstack_free
175void
176obstack_free (struct obstack *h, POINTER obj)
177#else
178int
179_obstack_free (h, obj)
180 struct obstack *h;
181 POINTER obj;
182#endif
183{
184 register struct _obstack_chunk* lp; /* below addr of any objects in this chunk */
185 register struct _obstack_chunk* plp; /* point to previous chunk if any */
186
187 lp = (h)->chunk;
188 /* We use >= because there cannot be an object at the beginning of a chunk.
189 But there can be an empty object at that address
190 at the end of another chunk. */
191 while (lp != 0 && ((POINTER)lp >= obj || (POINTER)(lp)->limit < obj))
192 {
193 plp = lp -> prev;
194 (*h->freefun) ((POINTER) lp);
195 lp = plp;
196 }
197 if (lp)
198 {
199 (h)->object_base = (h)->next_free = (char *)(obj);
200 (h)->chunk_limit = lp->limit;
201 (h)->chunk = lp;
202 }
203 else if (obj != 0)
204 /* obj is not in any of the chunks! */
205 abort ();
206}
207
208/* Let same .o link with output of gcc and other compilers. */
209
210#ifdef __STDC__
211int
212_obstack_free (h, obj)
213 struct obstack *h;
214 POINTER obj;
215{
216 obstack_free (h, obj);
217}
218#endif
219\f
220/* #if 0 */
221/* These are now turned off because the applications do not use it
222 and it uses bcopy via obstack_grow, which causes trouble on sysV. */
223
224/* Now define the functional versions of the obstack macros.
225 Define them to simply use the corresponding macros to do the job. */
226
227#ifdef __STDC__
228/* These function definitions do not work with non-ANSI preprocessors;
229 they won't pass through the macro names in parentheses. */
230
231/* The function names appear in parentheses in order to prevent
232 the macro-definitions of the names from being expanded there. */
233
234POINTER (obstack_base) (obstack)
235 struct obstack *obstack;
236{
237 return obstack_base (obstack);
238}
239
240POINTER (obstack_next_free) (obstack)
241 struct obstack *obstack;
242{
243 return obstack_next_free (obstack);
244}
245
246int (obstack_object_size) (obstack)
247 struct obstack *obstack;
248{
249 return obstack_object_size (obstack);
250}
251
252int (obstack_room) (obstack)
253 struct obstack *obstack;
254{
255 return obstack_room (obstack);
256}
257
258void (obstack_grow) (obstack, pointer, length)
259 struct obstack *obstack;
260 POINTER pointer;
261 int length;
262{
263 obstack_grow (obstack, pointer, length);
264}
265
266void (obstack_grow0) (obstack, pointer, length)
267 struct obstack *obstack;
268 POINTER pointer;
269 int length;
270{
271 obstack_grow0 (obstack, pointer, length);
272}
273
274void (obstack_1grow) (obstack, character)
275 struct obstack *obstack;
276 int character;
277{
278 obstack_1grow (obstack, character);
279}
280
281void (obstack_blank) (obstack, length)
282 struct obstack *obstack;
283 int length;
284{
285 obstack_blank (obstack, length);
286}
287
288void (obstack_1grow_fast) (obstack, character)
289 struct obstack *obstack;
290 int character;
291{
292 obstack_1grow_fast (obstack, character);
293}
294
295void (obstack_blank_fast) (obstack, length)
296 struct obstack *obstack;
297 int length;
298{
299 obstack_blank_fast (obstack, length);
300}
301
302POINTER (obstack_finish) (obstack)
303 struct obstack *obstack;
304{
305 return obstack_finish (obstack);
306}
307
308POINTER (obstack_alloc) (obstack, length)
309 struct obstack *obstack;
310 int length;
311{
312 return obstack_alloc (obstack, length);
313}
314
315POINTER (obstack_copy) (obstack, pointer, length)
316 struct obstack *obstack;
317 POINTER pointer;
318 int length;
319{
320 return obstack_copy (obstack, pointer, length);
321}
322
323POINTER (obstack_copy0) (obstack, pointer, length)
324 struct obstack *obstack;
325 POINTER pointer;
326 int length;
327{
328 return obstack_copy0 (obstack, pointer, length);
329}
330
331#endif /* __STDC__ */
332
333/* #endif 0 */
This page took 0.039528 seconds and 4 git commands to generate.