/* Language independent support for printing types for GDB, the GNU debugger.
Copyright (C) 1986, 1988, 1989, 1991, 1992, 1993, 1994, 1995, 1998, 1999,
- 2000, 2001, 2003, 2006, 2007, 2008, 2009 Free Software Foundation, Inc.
+ 2000, 2001, 2003, 2006, 2007, 2008, 2009, 2010, 2011
+ Free Software Foundation, Inc.
This file is part of GDB.
/* Print a description of a type in the format of a
typedef for the current language.
- NEW is the new name for a type TYPE. */
+ NEW is the new name for a type TYPE. */
void
typedef_print (struct type *type, struct symbol *new, struct ui_file *stream)
old_chain = make_cleanup (free_current_contents, &expr);
if (expr->elts[0].opcode == OP_TYPE)
{
- /* The user expression names a type directly, just use that type. */
+ /* The user expression names a type directly, just use that type. */
type = expr->elts[1].type;
}
else
{
/* The user expression may name a type indirectly by naming an
- object of that type. Find that indirectly named type. */
+ object of that type. Find that indirectly named type. */
val = evaluate_type (expr);
type = value_type (val);
}
Print definition of type TYPE.\n\
Argument may be a type name defined by typedef, or \"struct STRUCT-TAG\"\n\
or \"class CLASS-NAME\" or \"union UNION-TAG\" or \"enum ENUM-TAG\".\n\
-The selected stack frame's lexical context is used to look up the name."));
+The selected stack frame's lexical context is used to look up the name.\n\
+Contrary to \"whatis\", \"ptype\" always unrolls any typedefs."));
add_com ("whatis", class_vars, whatis_command,
- _("Print data type of expression EXP."));
+ _("Print data type of expression EXP.\n\
+Only one level of typedefs is unrolled. See also \"ptype\"."));
}